from math import ceil
def gcd(a,b):
if b == 0:
return a
else:
return gcd(b, a%b)
n,a,b=map(int,input().split())
x=list(map(int,input().split()))
for i in x:
maxpos = (i*a)//b
minreq = ceil((maxpos*b)/a)
print(i-minreq,end=' ')
#include <iostream>
#include <bits/stdc++.h>
#define ll long long int
#define ld long double
#define endl '\n'
#define f(n) for(int i=0 ;i<n;i++)
#define fast cin.tie(0), cout.tie(0), cin.sync_with_stdio(0), cout.sync_with_stdio(0);
using namespace std;
int main()
{
fast
ll n,a,b; cin>>n>>a>>b;
ll arr[n];
f(n)cin>>arr[i];
f(n)cout<<((arr[i]*a)%b)/a<<" ";
return 0;
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